SOLUTION: if a child walks at 5 km/h from his house and reaches his school 3 minutes late.however,if he walks at 6km/h,he reaches 5 minutes early.how far is the school from his house?

Question 697637:
if a child walks at 5 km/h from his house and reaches his school 3 minutes late.however,if he walks at 6km/h,he reaches 5 minutes early.how far is the school from his house?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
D=RT
D=5(T+3)
D=6(T-5)
5(T+3)=6(T-5)
5T+15=6T-30
5T-6T=-30-15
-T=-45
T=45 MINUTES IS THE TIME.
PROOF:
5(45+3)=6(45-5)
5*48=6*40
240=240
D=5(45+3) 5 KM/H* 48 MIN.
D=5*.8
D=4 KM. DISTANCE TO THE SCHOOL.
D=6(45-5) 6KM/H* 40 MIN.
D=6*2/3
D=12/3=4 KM. DITTO.
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