SOLUTION: You are taking a 6-hour train ride. During the 1st part of the trip, the train moves at an average speed 65 miles per hour. During the 2nd part of the trip, the train moves an aver

Question 694497: You are taking a 6-hour train ride. During the 1st part of the trip, the train moves at an average speed 65 miles per hour. During the 2nd part of the trip, the train moves an average speed of 40 miles per hour. Let L be the time it takes for the train to travel the 1st part of the trip. Write and simplify and expression in terms of t for the total distance you traveled in the train. Then find the total distance you traveled if the first part of the trip took 4 hours.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Total time = 6 hours
L = Time first part of trip
speed I part = 65 mph
Distance I part = 65 L
Time II part = 6 -L
Speed II part = 40 mph

Distance II part = 40(6-L)
Total Distance = 65L + (6-L)*40
=65L+240-40L
=25L+240
Total Distance =25L+240
If L=4
D= 100+240 =340 miles

RELATED QUESTIONS
You are taking a 6-hour train ride. During the first part of the trip, the train moves... (answered by ankor@dixie-net.com)

You ride in a train for 175 miles at an average speed of 50 miles per hour. How many... (answered by kiljoy)

you ride on a train for 175 miles at an average speed of 50 miles per hour. how many... (answered by rfer)

you ride on a train for 175 miles at an average speed of 50 miles per hour. how many... (answered by RAY100)

you ride in a train for 175 miles at an average speed of 50 miles per hour. how many... (answered by rfer)

you ride in a train for 175 miles at an average speed of 50 miles per hour/ How many... (answered by checkley77)

you ride in a train for 175 miles at an average speed of 50 miles per hour. how many... (answered by solver91311)

Please help me solve this word problem. The family trip to Grandma's consisted of both... (answered by unlockmath,NeedTrigHelp)

the family trip to grandma's consisted of both a train ride and a car ride. the average... (answered by josgarithmetic)