SOLUTION: The distance between two station is 192 k.m..How much time a train take to pass the stations the another train takes two hours more than the first.If the average speed of the secon
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Question 693284: The distance between two station is 192 k.m..How much time a train take to pass the stations the another train takes two hours more than the first.If the average speed of the second train is 16 k.m less than the first,then find out the average speed of both the trains ? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The distance between two stations is 192 k.m.
:
let s = speed of the 1st train
How much time does a train take to pass the stations? = hrs
:
The another train takes two hours more than the first.
If the average speed of the second train is 16 k.m less than the first,
then find out the average speed of both the trains ?
:
Write a time equation, time = dist/speed
2nd train time - 1st train time = 2 hr - = 2
multiply by s(s-16) to clear the denominators, resulting in:
192s - 192(s-16) = 2s(s-16)
:
192s - 192s + 3072 = 2s^2 - 32s
Arrange as a quadratic equation
0 = 2s^2 - 32s - 3072
Simplify, divide by 2
s^2 - 16s - 1536 = 0
you can us the quadratic formula here, but this will factor to:
(s-48)(s+32) = 0
The positive solution is what we want here
s = 48 km/h, the speed of the faster train
you can find the speed of the slower
