SOLUTION: Train A, is 10 meters from the station and is traveling at the rate of 5 meters per minute. Train B, started at the station and is traveling at the rate of 8 meters per minute. How
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Question 690959: Train A, is 10 meters from the station and is traveling at the rate of 5 meters per minute. Train B, started at the station and is traveling at the rate of 8 meters per minute. How much time will pass until they are in the same place? And explain why your answer is reasonable.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Train A, is 10 meters from the station and is traveling at the rate of 5 meters per minute. Train B, started at the station and is traveling at the rate of 8 meters per minute. How much time will pass until they are in the same place? And explain why your answer is reasonable.
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Train A DATA:
rate = 5m/min ; distance = x meters ; time = x/5 minutes
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Train B DATA:
rate = 8m/min ; distance = 10-x meters; time = (10-x)/8 minutes
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Equation:
time = time
x/5 = (10-x)/8
8x = 5(10-x)
8x = 50 - 5x
13x = 50
x = 3.8462 meters
x/5 = 0.7692 minutes = 46.2 seconds (time till they are at the same place)
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Cheers,
Stan H.
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