What is asked in the problem?

At what time will the cars be 330 miles apart?



Given:

at 10 am a car leaves a house at a rate of 60mph

at the same time, another car leace the same house at a rate of 50mph 

opposite direction



Representation:

Let x = time the car be 330miles apart.



Make a table from the information given:

              r    times    t      =     d

first car   60mph           x      =    60x

second car  50 mph          x      =    50x



Distance of the 1st car + distance of the 2nd car = 330



60 x + 50x = 330

      110x = 330

         x = 3



therefore, after 3 hours the two cars are 330 miles apart.





 

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