SOLUTION: Arianna took 2hours longer to drive 360 miles on the first day of a trip than she took to drive 270 miles on the second day. If her spped was the same both days what was the drivin

Question 68690: Arianna took 2hours longer to drive 360 miles on the first day of a trip than she took to drive 270 miles on the second day. If her spped was the same both days what was the driving time each day? Here is what I came up with. Can you help me figure this out? Thank you in advance.
270/t = 360/t+2
270(t+2)=360t
270t + 540 = 360t
540 = 120
t = ?
Found 2 solutions by rmromero, stanbon:
Answer by rmromero(383) (Show Source): You can put this solution on YOUR website!
Arianna took 2hours longer to drive 360 miles on the first day of a trip than she took to drive 270 miles on the second day. If her spped was the same both days what was the driving time each day? Here is what I came up with. Can you help me figure this out? Thank you in advance.
270/t = 360/t+2
270(t+2)=360t
270t + 540 = 360t <<<<<<<<<<< subtract 270t both sides
540 = 120 <<<<<<<<< you went wrong this part
t = ?

Correction:
It should be:
540 = 90t << divide both sides by 90 to solve for t
t = 6 mi./hr <<<<<<<< speed on the second day
t + 2 = 8 mi./hr <<<<<< speed on the first day
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Arianna took 2hours longer to drive 360 miles on the first day of a trip than she took to drive 270 miles on the second day. If her spped was the same both days what was the driving time each day?
-----------------
First Day DATA:
Distance= 360 miles ; Time= x+2 hrs ; Rate =d/t = 360/(x+2) mph
--------------
Second Day DATA:
Distance= 270 miles ; Time = x hrs ; Rate = d/t = 270/x mph
----------------
EQUATIOn:
rate day DISABLED_event_one= rate day two
360/(x+2) = 270/x
36/(x+2)=27/x
36x = 27x+54
9x=54
x=6 hrs (driving time on day two)
x+2= 8 hrs (driving time on day one)
----------------
Cheers,
Stan H.

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