SOLUTION: Could you please help me solve this problem? A sharpshooter intends to hit a target at a distance of 1000 yards with a gun that has a muzzle velocity of 1200 feet per second. Ne

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Question 676896: Could you please help me solve this problem?
A sharpshooter intends to hit a target at a distance of 1000 yards with a gun that has a muzzle velocity of 1200 feet per second. Neglecting air resistance, determine the gin's minimum angle of elevation "x" if the range "r" is given by r=1/32V0^2sin2x.
Thank you!
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A sharpshooter intends to hit a target at a distance of 1000 yards with a gun that has a muzzle velocity of 1200 feet per second.
Neglecting air resistance, determine the gin's minimum angle of elevation "x" if the range "r" is given by r=1/32V0^2sin2x.
:
1%2F32*Vo%5E2*sin(2x) = r
:
Vo=1200, convert 1000 yds to 3000 ft
1%2F32*1200%5E2*sin(2x) = 3000
:
1%2F32*1440000*sin(2x) = 3000
:
45000*sin(2x) = 3000
:
sin(2x) = 3000%2F45000
:
sin(2x) = .0667
:
Find the arc-sine using .0667
2x = 3.823
x = 3.823/2
x = 1.91 degrees