SOLUTION: two friends go running. Leaving from the same point, 1 heads south at 7 mph for 3 hours and then heads east at 5 mph for 1 hour. The other friend heads west for two hours at 6 mph

Algebra.Com
Question 675087: two friends go running. Leaving from the same point, 1 heads south at 7 mph for 3 hours and then heads east at 5 mph for 1 hour. The other friend heads west for two hours at 6 mph and then heads north at 5 mph for 2 hours. Which of the following expresses the distance, in miles, between the two friends after 4 hours?
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
 
We will use the notation: 

North = UP, South = DOWN, East = RIGHT, West = LEFT

We will indicate the first runner's path with green arrows,
starting at point P:

>>One heads south at 7 mph for 3 hours...<< 

So he or she goes 7×3 or 21 miles DOWNWARD from point P,
like this:



>>and then heads east at 5 mph for 1 hour.<<

So he or she turns and goes 5×1 or 5 miles TO THE RIGHT,
like this:




>> The other friend heads west for two hours at 6 mph <<

So he or she goes 2×6 or 12 miles LEFT from point P.


We will indicate the other runner's path with red arrows,
starting a point P, like this:



>>and then heads north at 5 mph for 2 hours.<<

So he or she turns and goes 5×2 or 10 miles UP,
like this: 



So at the end of 4 hours the first runner is at the end of
the green path and the other runner is at the end of the red path.
We want to know how far they are apart, so let's draw a blue line
between where the runners are after 4 hours:



Now we'll draw a horizontal and vertical black line so that the
blue line will be the hypotenuse of a big right triangle, like this:



We'll draw two points on the black lines directly
above and directly to the right of point P, like this:



Now we can see that the upper horizontal side of the big
right triangle is 12+5 or 17 miles and the vertical side
of the big right triangle is 10+21 or 31 miles.  Therefore
we can use the Pythagorean theoren and find the distance
between the runners (the blue line), which is the hypotenuse
of the big right triangle:

(distance between runners)² = 17² + 31²
(distance between runners)² = 289 + 961
(distance between runners)² = 1250
   distance between runners = √1250
   distance between runners = √625·2
   distance between runners = 25√2
   distance between runners is approximately 35.35533906 miles, which
you should round off as your teacher desires, perhaps to 35.4 miles.
   

Edwin

RELATED QUESTIONS

Two cars leave an intersection at the same time. One heads east at an average speed of 40 (answered by ramkikk66)
Two friends start running in different directions from the same place. One heads south,... (answered by ewatrrr)
Two vehicles a car and a truck leave an intersection at the same time the car heads east... (answered by stanbon,richwmiller)
Two planes leave from chicago at noon. One heads east at 420mph while the other heads... (answered by TimothyLamb)
Can you help me formulate an equation for the following homework problem? It did not come (answered by checkley75,stanbon)
Tom and Gary are leaving the same town for a meeting in different cities. However, they... (answered by ramkikk66)
Two cyclists start biking from the same location. Kate heads south at an average pace of... (answered by ewatrrr)
1. Cyrus start jogging from a certain point and runs 5 mph. Jaden jogs from the same... (answered by graphmatics)
Two vehicles, a car and a truck. leave an intersection at the same time. The car heads... (answered by drj)