SOLUTION: At noon, a jetliner left New York for Los Angeles 4000 kn away. At 1:00 P.M. New York time a jetliner, flying 10 km/hr faster than the first one, left Los Angeles for New York. T

Question 674406: At noon, a jetliner left New York for Los Angeles 4000 kn away. At 1:00 P.M. New York time a jetliner, flying 10 km/hr faster than the first one, left Los Angeles for New York. The planes passed each other at 3:00 P.M.New York time. Find the speed of the planes.

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let the speed of the NY_LA plane =
The NY-LA plane got a head start of km
The planes were then km apart
Let = distance in km that the NY-LA plane
has to travel until it meets the LA-NY plane
----------------------
NY-LA plane's equation:
(1) ( note that time starts at 1 PM and ends at 3 PM )
LA-NY plane's equation:
(2)
------------------------------
Substitute (1) into (2)
(2)
(2)
(2)
(2)
(2)

The speeds of the planes are:
NY-LA - 796 km/hr
LA-NY - 806 km/hr
-----------------
check answer:
(1)
(1)
(1) km
and
(2)
(2)
(2)
(2)
(2) km
OK

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