SOLUTION: During rush hour, Fernando can drie 20 miles using the side roads in the same time it takes to travel 15 miles on the freeway. If Fernandos rate on the side roads is 9mi/h faster t

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Question 66362: During rush hour, Fernando can drie 20 miles using the side roads in the same time it takes to travel 15 miles on the freeway. If Fernandos rate on the side roads is 9mi/h faster than his rate on the freeway, find his rate on the side roads.
Is the answer 29?
Thank you for your help :-)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
During rush hour, Fernando can drive 20 miles using the side roads in the same time it takes to travel 15 miles on the freeway. If Fernandos rate on the side roads is 9 mi/h faster than his rate on the freeway, find his rate on the side roads.
Is the answer 29?
:
Let s = his speed on the sideroads
Then (s-9) = his speed on the freeway
:
Write a time equation, time = dist/speed
side-road time = freeway time
20%2Fs = 15%2F%28%28s-9%29%29
:
Cross mult and you have:
20(s-9) = 15s
20s - 180 = 15s
20s - 15s = 180
5s = 180
s = 180/5
s = 36 mph on the side-roads
:
:
Check our solution using the time eq:
20/36 = 15/27
5/9 = 5/9 confirms our solution