SOLUTION: a plane can travel 1200 miles with the wind in 20 hours. on the return trip the plane can travel 2/3 the distance in the same amount of time. what is the speed of the plane and the

Question 659660: a plane can travel 1200 miles with the wind in 20 hours. on the return trip the plane can travel 2/3 the distance in the same amount of time. what is the speed of the plane and the speed of the wind?
i have already tried to solve this problem out, this is what i came up with:
(x+y)20=1200
(x-y)20=1800 ---> (1200/ (2/3) =1800)
i then put it in the equation in the calculator as matrices:
A[20 20] B[1200]
A[20 -20] B[1800]
i got [75]
[-15]
is this right? i heard from my teacher we are not supposed to have negatives but i'm not sure if i had set this equation right.. please help :(

Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
It's not right.
The return distance is 2/3*1200 = 800 not 1800.
Then you should get
x = 50
y = 10
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