SOLUTION: Two trains are approaching on the same track again, this time 100 km apart. Train A is going 30 km/h, and Train B is going 20 km/h. This time, the engineers send a passenger pigeo

Question 657814: Two trains are approaching on the same track again, this time 100 km apart. Train A is going 30 km/h, and Train B is going 20 km/h. This time, the engineers send a passenger pigeon between the two engines. The bird flies at 50 km/h, back and forth between the two approaching engines. Ignoring the time needed to untie, read, write responses, and re-tie the message on the poor bird's leg, how far will the bird have flown before the two trains collide? How many trips between the engines will the bird have flown?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two trains are approaching on the same track again, this time 100 km apart. Train A is going 30 km/h, and Train B is going 20 km/h. This time, the engineers send a passenger pigeon between the two engines. The bird flies at 50 km/h, back and forth between the two approaching engines. Ignoring the time needed to untie, read, write responses, and re-tie the message on the poor bird's leg, how far will the bird have flown before the two trains collide? How many trips between the engines will the bird have flown?
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Traiin A DATA:
rate = 30 km/h ; time = x hrs ; distance = 30x km
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Train B DATA:
rate = 20 km/h ; time = x hrs; distance = 20x km
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Solve for "x":
30x + 20x = 100 km
50x = 100 km
x = 2 hrs
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How far does the bird fly?
distance = rate*time
d = 50 km/h *2 hr = 100 km
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How many trips will the bird fly?
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Cheers,
Stan H.
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