You can
put this solution on YOUR website!Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initially 5.0 km east of the flagpole and is running with a constant velocity of 8.0 km/h due west. What will be the distance of the two runners from the flagpole when their paths cross?
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At the start runner A and runner B are 11 km apart.
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Eastbound runner DATA:
distance=x km ; rate= 9 k/h ; time= d/r=x/9 hr
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Westbound runner DATA:
distance = 11-x ; rate= 8 k/h ; time = d/r = (11-x)/8
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EQUATION:
time east= time west
x/9= (11-x)/8
8x=99-9x
17x=99
x=5.92 km (distance eastbound runner goes)
He will meet the westbound runner 6-5.92=0.08 km west of the flagpole.
Cheers,
Stan H.
You can
put this solution on YOUR website!The runner running west has velocity
km/hr
He runs adistance
km
and meets the other runner after
hours
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The runner running east has velocity
km/hr
He runs adistance
km
and meets the other runner after
hours
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Their velocities and therefore, distances are different,
but they each run for the same amount of time in order
to meet eachother, so,
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and
, therefore
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km
If I say
, then
km
km
The runner 1 went the shorter distance in the same time
as runner 2, but he still passed the flagpole before
runner 2, and ended up .1765 km on the west side of it.
Runner 2 met him there (6 - 5.8235) km short of the
flagpole, or .1765 km short.
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