SOLUTION: A baseball is hit by Ordonez at an initial velocity of 145 feet per second. Using the equation of height versus time h= -16t^2+v0t+h0 , where h is height at a given time, v0 is ini

Question 655160: A baseball is hit by Ordonez at an initial velocity of 145 feet per second. Using the equation of height versus time h= -16t^2+v0t+h0 , where h is height at a given time, v0 is initial velocity, and h0 is the initial height, what is the maximum height the ball reaches assuming no wind resistance? How long does the ball stay in the air?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
A baseball is hit by Ordonez at an initial velocity of 145 feet per second. Using the equation of height versus time h= -16t^2+v0t+h0 , where h is height at a given time, v0 is initial velocity, and h0 is the initial height,
.
Assuming the initial height was 4 feet (chest level) then
Your equation is:
h= -16t^2+145t+4
.
what is the maximum height the ball reaches assuming no wind resistance?
max height is at the vertex:
t value at vertex:
t = -b/2a
t = -145/(2*(-16))
t = -145/(-32)
t = 4.53 sec
.
height at that time is:
h= -16t^2+145t+4
h= -16(4)^2+145(4)+4
h= 328 feet
.
How long does the ball stay in the air?
set h to zero and solve for t:
h= -16t^2+145t+4
0= -16t^2+145t+4
solving for t using the "quadratic formula" yields:
t = {-0.03, 9.10}
throw out the negative solution leaving
t = 9.1 seconds

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