SOLUTION: I would like the details on how the problem was solved.
Perry left school driving towards the lake one hour before Jaidee. Jaidee drove in the opposite direction going 6 mph
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Question 649000: I would like the details on how the problem was solved.
Perry left school driving towards the lake one hour before Jaidee. Jaidee drove in the opposite direction going 6 mph slower than Perry for one hour after which time they were 174mi. apart. What was Parry's speed?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Perry left school driving towards the lake one hour before Jaidee. Jaidee drove in the opposite direction going 6 mph slower than Perry for one hour after which time they were 174mi. apart. What was Parry's speed?
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Perry DATA:
time = 2 hrs ; rate = r mph ; distance = r*t = 2r miles
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Jaidee DATA:
time = 1 hr ; rate = r-6 mph ; distance = r-6 miles
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Equation:
distance + distance = 174 miles
2r + r-6 = 174
----
3r - 6 = 174
3r = 180
r = 60 mph (Perry's rate)
r-6 = 54 mph (Jaidee's rate)
======================
Cheers,
Stan H.
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