SOLUTION: sue walks at a rate of 10 feet every 5 seconds while tom walks at a rate of 15 feet every 5 seconds. If sue has a head start of 25 feet, after how many seconds will they be at the

Question 648934: sue walks at a rate of 10 feet every 5 seconds while tom walks at a rate of 15 feet every 5 seconds. If sue has a head start of 25 feet, after how many seconds will they be at the same spot?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Sue walks at a rate of 10 feet every 5 seconds while tom walks at a rate
of 15 feet every 5 seconds.
If sue has a head start of 25 feet, after how many seconds will they be at the
same spot?
:
Change the speeds to ft/sec
Sue: 10/5 = 2 ft/sec
Tom: 15/5 = 3 ft sec
:
Let t = time (in sec) for T to catch S
:
When T catches S, T will have walked 25 more ft than S
Write a distance equation; dist = speed * time
:
3t = 2t + 25
3t - 2t = 25
t = 25 sec for Tom to catch Sue
:
:
Confirm this,
Tom: 3(25) = 75ft
Sue: 2(25) = 50ft; plus her 25 ft head start = 75 ft
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