SOLUTION: Travel by car: Marcus drives from one town to another in 6 hours. On the return trip, his speed increased by 10 mph and the trip takes 5 hours. Find his rate on the return trip. Ho
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Question 648824: Travel by car: Marcus drives from one town to another in 6 hours. On the return trip, his speed increased by 10 mph and the trip takes 5 hours. Find his rate on the return trip. How far apart are the towns?
So far I know:
rate x time= distance
Going trip- rate= r time =6 distance= ?
Return trip- rate= r+10 time= 5 distance=?
I am not sure how to proceed in writing and solving the equation.
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Travel by car: Marcus drives from one town to another in 6 hours. On the return trip, his speed increased by 10 mph and the trip takes 5 hours. Find his rate on the return trip. How far apart are the towns?
So far I know:
rate x time= distance
Going trip- rate= r time =6 distance= ?
Return trip- rate= r+10 time= 5 distance=?
I am not sure how to proceed in writing and solving the equation.
Let the town he left from be town A and the town he went to, town B
Let rate of speed from town B to town A, be S
Then speed from town A to town B = S - 10
Distance from town A to town B equals distance from town B to town A, OR
6(S – 10) = 5S
6S – 60 = 5S
6S – 5S = 60
S, or speed on return trip (from town B to town A) = mph
Distance between the towns = 6(60 – 10), or 5(60), or miles.
You can do the check!!
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