SOLUTION: The revenue and cost equations for a product are
R=x(50-0.0002x) and C=12x+150,000
where R and C are measured in dollars and x represents the number of units sold. How many units
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Question 647843: The revenue and cost equations for a product are
R=x(50-0.0002x) and C=12x+150,000
where R and C are measured in dollars and x represents the number of units sold. How many units must be sold be obtain a profit of at least $1,650,000?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The revenue and cost equations for a product are
R=x(50-0.0002x) and C=12x+150,000
where R and C are measured in dollars and x represents the number of units sold. How many units must be sold be obtain a profit of at least $1,650,000?
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Profit = Revenue - Cost
P = x(50-0.0002x)-(12x+150,000)
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P = 50x - 0.0002x^2 - 12x - 150000
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P(x) = -0.0002x^2 + 38x -150000
----
Solve: -0.0002x^2 + 38x -150000 >= 1650000
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etc.
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Cheers,
Stan H.
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