SOLUTION: A diesel train left Washington and traveled
toward Johannesburg at an average speed of
52 mph. A cattle train left two hours later
and traveled in the same direction but with
Algebra.Com
Question 643805: A diesel train left Washington and traveled
toward Johannesburg at an average speed of
52 mph. A cattle train left two hours later
and traveled in the same direction but with
an average speed of 60 mph. Find the
number of hours the diesel train traveled
before the cattle train caught up
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A diesel train left Washington and traveled toward Johannesburg at an
average speed of 52 mph.
A cattle train left two hours later and traveled in the same direction
but with an average speed of 60 mph.
Find the number of hours the diesel train traveled before the cattle train
caught up.
:
Let t = travel time of the diesel train
then
(t-2) = travel time of the cattle train (Left 2 hrs later)
:
When the cattle train catches the diesel, they will have traveled the
same distance. Write a distance equation. Dist = speed * time
52t = 60(t-2)
52t = 60t - 120
120 = 60t - 52t
120 = 8t
t = 120/8
t = 15 hrs
:
:
Confirm this by finding the distance of each, should be equal
52(15) = 780 mi
60(13) = 780 mi also
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