SOLUTION: Paul and Charlene are 420 miles apart. They start toward each other with Paul driving 16mi/h faster than Charlene. They meet in 5 hours. Find Carlene's speed.
Any help is app
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Question 64037: Paul and Charlene are 420 miles apart. They start toward each other with Paul driving 16mi/h faster than Charlene. They meet in 5 hours. Find Carlene's speed.
Any help is appreciated.
Found 3 solutions by josmiceli, ankor@dixie-net.com, checkley71:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
because (they meet at the same time)
given
given
Charlene's speed is 34 mi/hr
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Paul and Charlene are 420 miles apart. They start toward each other with Paul
driving 16 mi/h faster than Charlene. They meet in 5 hours. Find Carlene's speed.
:
Let s = Carlene's speed
Let (s+16) = Paul's speed
:
Write a dist equation; dist = time * speed
:
Paul's dist + Carlene's dist = 420
5(s+16) + 5s = 420
5s + 80 + 5s = 420
10s = 420 - 80
10s = 340
s = 340/10
s = 34 mph is Carlene's speed
:
:
Check using the distance equation:
5(34) + 5(50) =
170 + 250 = 420 mi
:
Could you follow this OK. Any questions?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
450=5(x+x+16)
450=5x+5x+80
10x=450-80
10x=370
x=37/10
x=37 mph solution for Charline's speed.
37+16=53 mph for Paul's speed
proof
450=5*37+5*53
450=185+265
450=450
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