SOLUTION: x & y travel 4000m n finish race in tie.first x travel 50% than Y and Y travels 50% faster than x n end in tie.before y travelled 50% faster then X what distance had it covered?
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Question 637688: x & y travel 4000m n finish race in tie.first x travel 50% than Y and Y travels 50% faster than x n end in tie.before y travelled 50% faster then X what distance had it covered? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Attempt to rewrite this so it makes sense.
:
x & y travel 4000m and finish the race in a tie.
At first x travels 50% faster than Y and then,
Y travels 50% faster than x, and the race ends in a tie.
Before y traveled 50% faster then X, what distance had he covered?
:
let s = the original speed of y
and
1.5s = the original speed of x
then
1.5(1.5s)= 2.25s = final speed of y
:
Let d = distance y traveled at speed s
then
(4000-d) = speed y traveled at speed 2.25s
:
Write a time equation:
y's total travel time = x's travel time + =
Multiply by least common multiple: 27s
27s* + 27s* = 27s*
Cancel out the denominators, results:
27d + 12(4000-d) = 18(4000)
27d + 48000 - 12d = 72000
27d - 12d = 72000 - 48000
15d = 24000
d =
d = 1600 meters traveled before y changed his speed to 1.5 times x's speed
