SOLUTION: If an object is thrown upward with an initial velocity of 112ft/sec, it's height after t sec is given by h=112t-16t^2. how long will it take for the object to reach it's maximum h

Question 636125: If an object is thrown upward with an initial velocity of 112ft/sec, it's height after t sec is given by h=112t-16t^2. how long will it take for the object to reach it's maximum height?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

 h=  -16t^ + 112t    Note: 

 h =  -16(t-7/2)^2 + 16*49/4

  h =  -16(t-7/2)^2 + 196  



Note: vertex form of a Parabola opening up(a>0) or down(a<0),  

where(h,k) is the vertex  



Parabola opening Downward  V(3.5,196)

how long will it take for the object to reach it's maximum height?  

 will take 3.5 sec to reach max height of 196 ft 

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