SOLUTION: airplane 1 travels 500 mph ; airplane 2 travels 600 mph ; airplane 2 leaves 30 minutes after airplane 1 ; at what time will airplane 2 catch airplane 1 ?

Question 63359: airplane 1 travels 500 mph ; airplane 2 travels 600 mph ; airplane 2 leaves 30 minutes after airplane 1 ; at what time will airplane 2 catch airplane 1 ?

Found 2 solutions by checkley71, pftsta3:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
500T=600(T-2.5)
500T=600T-1500
-100T=-1500
T=-1500/-100
T=15 HOURS AFTER THE FIRST PLANE LEAVES THE SECOND PLANE WILL CATCH IT.
PROOF
500*15=600(15-2.5)
7500=600*12.5
7500=7500
Answer by pftsta3(3) (Show Source): You can put this solution on YOUR website!

Airplane 2 will travel in the air 30 minutes behind airplane 1, ALWAYS. It will take 3 hours until airplane 2 catches up to airplane 1. After 3 hours and 30 mintues, airplane 1 will travel 1750 miles while after 3 hours in the air, airplane 2 will travel 1800 miles.
A= Airplane
A1=****
A2= ^^^^^
600 miles 1200 miles 1800 miles
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
30m 1hr 30m 1hr 30m 1hr 30m
____________________________________________________________________________
*****************************************************************************
750 miles 1250 miles 1750 miles
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