Question 632364: Sandy and Kelvin live 385 miles apart. They each leave home at 3:00 P.M. Sandy drives 60 mph, and Kelvin drives 50 mph. At what time will they meet?
Found 3 solutions by Alan3354, ewatrrr, rapaljer:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Sandy and Kelvin live 385 miles apart. They each leave home at 3:00 P.M. Sandy drives 60 mph, and Kelvin drives 50 mph. At what time will they meet?
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What direction do they drive?
Answer by ewatrrr(24785)  (Show Source):
You can put this solution on YOUR website!
Hi,
Question states*** They each drive the same amount of time: t = D/r
Let x represent the amount of distance driven by Kelvin
 | Cross Multiplying to solve
60x = 50(385-x)
110x = 19250
x = 175, distance driven by Kelvin. t = 175/50 =3.5 hrs
left home at 3:00 P.M. met at 6:30 P.M.
and(just checking...) Sandy's time = 210/60 = 3.5 hrs
Answer by rapaljer(4671)  (Show Source):
You can put this solution on YOUR website! Let x = number of hours driving until they meet.
Distance of Sandy = R*T = 60x
Distance of Kelvin = R*T= 50x
Total Distance = 385 miles
60x + 50x = 385
110x = 385
x=385/110=3 55/110
x=3.5 hours
Since they left at 3:00 pm, add 3.5 hours, and they will meet at 6:30 pm.
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