SOLUTION: A bicycle rider left at 6 a.m. city A to city B at the speed of 15 km an hour. At 8 a.m. a car left city A for city B at the speed of 75 km an hour.
The car arrived to B, stayed t
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Question 631327: A bicycle rider left at 6 a.m. city A to city B at the speed of 15 km an hour. At 8 a.m. a car left city A for city B at the speed of 75 km an hour.
The car arrived to B, stayed there 2 hours and started driving back to A at the same speed. After a 1/4 of the way back the car met the bicycle.
What is the distance between A to B?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A bicycle rider left at 6 a.m. city A to city B at the speed of 15 km an hour.
At 8 a.m. a car left city A for city B at the speed of 75 km an hour.
The car arrived to B, stayed there 2 hours and started driving back to A at the
same speed.
After a 1/4 of the way back the car met the bicycle.
What is the distance between A to B?
:
Let d = distance from A to B
then when they met:
.75d = distance traveled by the bike
1.25d = distance traveled by the car
:
From the information given, we know the bike travel time was 4 hrs more than the car.
(The car left two hrs after the bike and stayed at B for 2 hrs}
:
Write a time equation: time = dist/speed
:
Bike time - car time = 4 hrs
- = 4
multiply by 75
5(.75d) - 1.25d = 75(4)
3.75d - 1.25d = 300
2.50d = 300
d = 300/2.50
d = 120 km from A to B
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