SOLUTION: Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had traveled 4 mph faster, she could have made the trip in 1/2 hr less time.

Question 628664: Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had traveled 4 mph faster, she could have made the trip in 1/2 hr less time. How far apart are the towns?
Found 2 solutions by dfrazzetto, MathTherapy:
Answer by dfrazzetto(283) (Show Source): You can put this solution on YOUR website!
d = v*t
V1 = 32 mph
V2 = 32+4 = 36 mph
t1 = t
t2 = t - 1/2
distance is from one town to the other, so d1 and d2 are the same, set them equal
v1*t1 = v2*t2
32t = 36(t-1/2)
32t = 36t - 18
4t = 18
t = 4.5 hrs
d = v1*t1 = v2*t2 = 32(4.5) = 36(4) = 144 miles
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!

Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had traveled 4 mph faster, she could have made the trip in 1/2 hr less time. How far apart are the towns?

Let distance between the towns be D

Then:

9D � 8D = 144 ----- Multiplying by LCD, 288

D, or distance between the towns = miles

Send comments and �thank-yous� to �D� at MathMadEzy@aol.com
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