SOLUTION: Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 k
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Question 628629: Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. Find the distance between P and Q.
Need answer with solution urgently.. Thanks a million..
Found 2 solutions by richwmiller, MathTherapy:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Answer by MathTherapy(10551) (Show Source): You can put this solution on YOUR website!
Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. Find the distance between P and Q.
Need answer with solution urgently.. Thanks a million..
Let distance traveled by faster train be D
Then distance traveled by slower train = D - 100
Time taken by faster train to travel to meeting point = time taken by slower train to travel to the meeting point, OR
50(D – 100) = 40D ------ Cross-multiplying
50D – 5,000 = 40D
50D - 40D = 5,000
10D = 5,000
D, or distance traveled by faster train = , or km
Distance traveled by slower train = 500 – 100, or km
Therefore, distance between P and Q = 500 + 400, or km
You can do the check, I'm sure!!
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