SOLUTION: The height if a projectile with an initial velocity of 160 feet per second and an initial height of 70ft is a function of time t, in seconds, given by h(t)= -16t^2+160t+70, find th

Question 623810: The height if a projectile with an initial velocity of 160 feet per second and an initial height of 70ft is a function of time t, in seconds, given by h(t)= -16t^2+160t+70, find the time t whgen the projectile reaches its max height.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
The height if a projectile with an initial velocity of 160 feet per second and an initial height of 70ft is a function of time t, in seconds, given by h(t)= -16t^2+160t+70, find the time t whgen the projectile reaches its max height.
**
h(t)= -16t^2+160t+70
This is an equation of a parabola that opens downwards of the form:
y=(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex of which y=maximum.
complete the square
-16(t^2-10t+25)+70+400
-16(t-5)^2+470
vertex: (5,470)
projectile reaches maximum height of 470 ft after 5 seconds

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