SOLUTION: Ok, I hope you can help it's been driving me nuts for a while now. Train leaves at 9 am at a speed of 65km/hr straight. At 10:30 am a car leaves the same station at 115km/hr. A) Ho

Question 621569: Ok, I hope you can help it's been driving me nuts for a while now. Train leaves at 9 am at a speed of 65km/hr straight. At 10:30 am a car leaves the same station at 115km/hr. A) How far from the station does the car catch up with the train? B) What was the cars average velocity in meters per second? C) If the car had not left the train station until 11am and the train still travels at 65km/hr, how fast would the car have to go to catch up to the train at the same distance from the station as in part A in Km/hr?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
After receiving your note I checked the problem you referred to and found I had made a mistake, getting the car and the train mixed up, I will correct that here.
Train leaves at 9 am at a speed of 65km/hr straight.
At 10:30 am a car leaves the same station at 115km/hr.
:
A) How far from the station does the car catch up with the train?
Let t = travel time of the train
From the information given we know
(t-1.5) = travel time of the car (left an hour and half later)
When the car catches the train, they will have traveled the same distance
Write a distance equation; dist = speed * time
115(t-1.5) = 65t
115t - 172.5 = 65t
115t - 65t = 172.5
50t = 172.5
t = 172.5/50
t = 3.45 hrs is the travel time of the TRAIN
therefore
3.45 * 65 = 224.25 km
Check using the CAR (travel time 1.5 hrs less)
1.95 * 115 = 224.25
:
B) What was the cars average velocity in meters per second?
Find the no. of meters traveled in one hr, divide by 3600 sec
= 31.94 m/sec
:
C) If the car had not left the train station until 11am and the train still travels at 65km/hr, how fast would the car have to go to catch up to the train at the same distance from the station as in part A in Km/hr?
:
let s = speed of the car to accomplish this
travel time of the car is now; 3.45 - 2 = 1.45 hrs
1.45s = 224.25
s = 224.25/1.45
s = 154.655 km/hr to catch the train in 1.45 hrs

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