# SOLUTION: a train travelling at 60 mph takes 6 sec to enter a tunnel and a further 30 sec to pass completely through the tunnel. what is the length of the train and what is the length of the

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: a train travelling at 60 mph takes 6 sec to enter a tunnel and a further 30 sec to pass completely through the tunnel. what is the length of the train and what is the length of the      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Travel and Distance Solvers Lessons Answers archive Quiz In Depth

 Question 618660: a train travelling at 60 mph takes 6 sec to enter a tunnel and a further 30 sec to pass completely through the tunnel. what is the length of the train and what is the length of the tunnel. Answer by Edwin McCravy(8999)   (Show Source): You can put this solution on YOUR website!```Since 1 hour is 3600 seconds, 1 second is 1/3600th of an hour, so 6 seconds is 6/3600ths of an hour of 1/600th of an hour 30 seconds is 30/3600ths of an hour of 1/120th of an hour Let the train's length be x mi. Let the tunnel's length by y mi. When the front of the train is at the tunnel entrance, the rear of the train is x mi. from the tunnel entrance. It then takes the rear of the train 1/600th of an hour to get to the entrance of the tunnel. In that time the rear of the train has traveled exactly one train-length or x mi (to get to the tunnel entrance). DISTANCE = RATE·TIME so x = 60· = = of a mile. So the train is of a mile long. (which is 528 feet) It then takes 1/120th of an hour for the rear of the train to get from the tunnel entrance to the tunnel exit. In that time the rear of the train has traveled exactly one tunnel-length or y mi. DISTANCE = RATE·TIME so y = 60· = = of a mile. So the tunnel is of a mile long. Edwin```