SOLUTION: Joe leaves traveling at 40 mph and 3 hours later Sue follows at 60 mph. How far have they gone before Sue catches up?

Question 617679: Joe leaves traveling at 40 mph and 3 hours later Sue follows at 60 mph. How far have they gone before Sue catches up?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Joe leaves traveling at 40 mph and 3 hours later Sue follows at 60 mph. How far have they gone before Sue catches up?
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let x=travel time of Sue
3+x=travel time of Joe
Both traveled the same distance
Distance=speed*travel time
60x=40(3+x)
60x=120+40x
20x=120
x=6
60x=360
Sue catches up after traveling 360 mi

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