SOLUTION: When a ball is thrown in the air, the height h of a ball in feet t seconds after the ball is thrown in the air, is given by the equation height = 25t–16t²
Use the quadratic equ
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Question 608468: When a ball is thrown in the air, the height h of a ball in feet t seconds after the ball is thrown in the air, is given by the equation height = 25t–16t²
Use the quadratic equation to determine how many seconds goes by before the ball hits the ground?
Answer by flame8855(424) (Show Source): You can put this solution on YOUR website!
when it hits the ground, height = 0
16t^2 -25t=0
t(16t-25) = 0
t = 0 , (at the beginning of the throw,
or
t = 25/16 seconds
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