SOLUTION: a tortoise and a hare decide to reenact the fabled race between their species, but this time with a slight twist. They start at the same place, but to be fair, the hare gives the t

Question 598124: a tortoise and a hare decide to reenact the fabled race between their species, but this time with a slight twist. They start at the same place, but to be fair, the hare gives the tortoise a 40- second head start. If the tortoise runs at a constant speed of 3 meters per second, and the hare runs at a constant speed of 11 meters per second, how many meters will the hare run until he catches the tortoise?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a tortoise and a hare decide to reenact the fabled race between their species, but this time with a slight twist.
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They start at the same place, but to be fair, the hare gives the tortoise a 40- second head start. If the tortoise runs at a constant speed of 3 meters per second, and the hare runs at a constant speed of 11 meters per second, how many meters will the hare run until he catches the tortoise?
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Hare DATA:
time = x sec ; rate = 11 m/s ; distance = 11x meters
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Tortoise DATA:
time = x sec ; rate = 3 m/s ; distance = 3x meters
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Equations:
t-distance + t-distance = h-distance
3x + 3*40 = 11x
3x + 120 = 11x
8x = 120
x = 15 seconds
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Hare distance: 11x = 165 meters
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Cheers,
Stan H.

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