SOLUTION: Kent drives his Mazda 270 miles in the same time Dave drives his Honda 250 miles. If Kent averages 4 miles per hour faster than Dave, find their speeds.
Thank you, Trudy
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Question 596046: Kent drives his Mazda 270 miles in the same time Dave drives his Honda 250 miles. If Kent averages 4 miles per hour faster than Dave, find their speeds.
Thank you, Trudy
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Distance equals rate times time, therefore time equals distance divided by rate.
Let 
represent the slower guy's rate then 
must be the faster guy's rate. The time's are equal, so let 
represent the time.
Slow guy's trip: 
Fast guy's trip: 
Since 
we can say:
Solve for , then compute 
John
My calculator said it, I believe it, that settles it
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