SOLUTION: Two airplanes leave the Atalnta airport at th esame time, traveling in opposite directions. One plane travels 30 miles per hour faster than the other. After 3 hours, the planes ar
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Question 59074: Two airplanes leave the Atalnta airport at th esame time, traveling in opposite directions. One plane travels 30 miles per hour faster than the other. After 3 hours, the planes are 3150 miles apart. what is the rate of each plane?
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Two airplanes leave the Atalnta airport at the same time, traveling in opposite directions. One plane travels 30 miles per hour faster than the other. After 3 hours, the planes are 3150 miles apart. what is the rate of each plane?
distance (d) = rate (r)* time(t)
Time for both planes is: t=3
One planes rate (r) is: x+30
The other's rate (r) is: x
The distance of one plane is: rt=tr=3(x+30)
The distance of the other is: rt=tr=3x
Since they're going in oppostie directions, if we add their two distances together you get: 3150
:
The equation to solve is:
3(x+30)+3x=3150
3x+90+3x=3150
6x+90=3150
6x+90-90=3150-90
6x=3060
6x/6=3060/6
x=510
:
One plane flew at: x+30=510+30=540 mph
The other flew at: x=510 mph
:
Check if both planes flew at that rate for 3 hours would they be 3150 miles apart?
3(540)+3(510)=3150
1620+1530=3150
3150=3150 We're right!!
Happy Calculating!!!
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