# SOLUTION: The distance D that a spring is stretched by hanging object varies directly as the weight W of the object. If a 6-kg object streches a spring 19cm, find the distance the spring is

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 Question 587885: The distance D that a spring is stretched by hanging object varies directly as the weight W of the object. If a 6-kg object streches a spring 19cm, find the distance the spring is streched when the weight is 19kg.Found 2 solutions by stanbon, lwsshak3:Answer by stanbon(57307)   (Show Source): You can put this solution on YOUR website!): The distance D that a spring is stretched by hanging object varies directly as the weight W of the object. --- D = kW ---- Solve for "k" using "a 6-kg object streches a spring 19cm" 19 = k*6 k = 19/6 ------------------- Equation: D = (19/6)W Find the distance the spring is stretched when the weight is 19kg D = (19/6)*19 D = 60.2 cm =================== Cheers, Stan H. ==================== Answer by lwsshak3(6492)   (Show Source): You can put this solution on YOUR website!The distance D that a spring is stretched by hanging object varies directly as the weight W of the object. If a 6-kg object streches a spring 19cm, find the distance the spring is streched when the weight is 19kg. ** D=(19/6)*19==≈60.17 cm