SOLUTION: A jumbo jet left an airport at the same time as a small private plane that followed the same flight plan during the first hour of its flight. The speed of the jet was 5 times that

Question 5722: A jumbo jet left an airport at the same time as a small private plane that followed the same flight plan during the first hour of its flight. The speed of the jet was 5 times that of the small one, and at the end of the hour it was 500 mi ahead. What was the speed of the larger plane?
Answer by guapa(62) (Show Source): You can put this solution on YOUR website!
Let x represent the speed of the private plane. Then 5x is the speed of the jet.
|----------------------------------->----------------------------------------->
|Distance of small plane in 1 hour |
|--------------------Distance of the jumbo jet in one hour--------------------|
Therefore we can say that the distance of the jet minus the distance of the private plane equals 500 miles. Let's set up the equation.
5x - x = 500 Combine like terms
4x = 500 Divide both sides by 4
4x/4 = 500/4
x = 125
Let's check:
5(125) - 125 = 500
625 - 125 = 500
500 = 500
The speed of the private plane is 5 times the small one. 5x = 5(125) = 625
The speed of the larger plane was 625 miles/hour.
Hope it helps
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