SOLUTION: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=104t-16t^2 . What is the maximum height that the ball will reach?

Question 572108: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=104t-16t^2 . What is the maximum height that the ball will reach?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=104t-16t^2 . What is the maximum height that the ball will reach?
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It's a parabola, and the max is the vertex.
The vertex is on the Line of Symmetry.
LOS is t = -b/2a
t = -104/(-32) = 3.25 seconds
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h(3.25) = 169 feet
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