SOLUTION: Two Jets are traveling torward each otherand are 4000km apart. The rate of one jet is 100 km/h faster than the rate of the other. If the jets pass each other after 2.5 hours, what

Question 57169: Two Jets are traveling torward each otherand are 4000km apart. The rate of one jet is 100 km/h faster than the rate of the other. If the jets pass each other after 2.5 hours, what is the rate of the faster jet
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
SORRY DIDN'T READ THE ENTIRE PROBLEM. THEY ARE ASKING FOR THE FASTEST WHICH WOULD BE 750=100 OR 850 KM/H.
DISTANCE = RATE TIMES TIME
4000=[X+(X+100)]2.5
4000=(2X+100)2.5
4000=5X+250
5X=4000-250
5X=3750
X=3750/5
X=750
PROOF
4000=(750+850)2.5
4000=1600*2.5
4000=4000
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