SOLUTION: Two cars left an intersection at the same time. One traveled north. The other traveled 6 miles farther, but to the easy. How far did the car going east travel when the distance bet

Question 568273: Two cars left an intersection at the same time. One traveled north. The other traveled 6 miles farther, but to the easy. How far did the car going east travel when the distance between the two cars was 30 miles?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
they are traveling at right angles to each other.
At any given instant they form a right triangle with their starting point

distance of one from starting point= x North bound
other = x+6 East bound

X^2 + (x+ 6 }^2 = 30 ^2
*
X^2 + X^2+ 12 x + 36 = 900

2 X^2 + 12 x -864 = 0
/2
x^2+6x -432
x^2+24x-18x-432=0
x(x+24)-18(x+24)=0
(x+24)(x-18)=0
x=24 OR 18
x=18 distance of north bound from starting point.
ignore negative since distance cannot be negative
distance of east bound will be = 18+6 = 24 miles from the starting point
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