SOLUTION: A canoe in still water travels at a rate of 10 miles per hour. The current today is traveling at a rate of 3 miles per hour. If it took an extra hour to travel upstream, how far wa
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Question 566175: A canoe in still water travels at a rate of 10 miles per hour. The current today is traveling at a rate of 3 miles per hour. If it took an extra hour to travel upstream, how far was the trip one way?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A canoe in still water travels at a rate of 10 miles per hour.
The current today is traveling at a rate of 3 miles per hour.
If it took an extra hour to travel upstream, how far was the trip one way?
:
Let d = the distance one way
:
10-3 = 7 mph is the effective speed against the current
:
Write a time equation; time = dist/speed
:
against current time = no current time + 1 hr
= + 1
multiply by 70, results
10d = 7d + 70
10d - 7d = 70
3d = 70/3
d = 23 mi
:
:
Check this by finding the times:
23.33/7 = 3.33 hrs
23.33/10= 2.33 hrs
---------------------
time dif: 1 hrs
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