SOLUTION: Can anyone help me with this one? thank you.
The height of an object tossed upward with an initial velocity of 104 feet per second is given by the formula h= -16t^2 + 104t, w
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: Can anyone help me with this one? thank you.
The height of an object tossed upward with an initial velocity of 104 feet per second is given by the formula h= -16t^2 + 104t, where h is the height in feet and t is the time in seconds. Find the time required for the object to return to its point of departure.
This question is from textbook college algebra
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
The height of an object tossed upward with an initial velocity of 104 feet per second is given by the formula h= -16t^2 + 104t, where h is the height in feet and t is the time in seconds. Find the time required for the object to return to its point of departure.
:
When the object hits the ground, h=0. So set the equation =0 and solve for t.
t=0, this is the time when the object was thrown.
The object will return to its point of departure at t=6.5 s.
Happy Calculating!!!
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