SOLUTION: Please help me solve below;
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyc
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Question 564084: Please help me solve below;
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Cyclist I 6 mph
Cyclist II 10 mph
Difference in time= 3 hours
Cyclist I will have covered 18 m before Cyclist II starts
catch up distance= 18 m
catch up speed = 10 -6 mph
catch up speed = 4 mph
Catchup time = catchup distance/catch up speed
catch up time= 18 / 4
catch up time= 4.5 hours
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