SOLUTION: The height of an object thrown upward with an initial velocity of 32 feet per second is given by the formula h=-16t^2+32t, where t is the time in seconds. How long will it take th
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Question 562382: The height of an object thrown upward with an initial velocity of 32 feet per second is given by the formula h=-16t^2+32t, where t is the time in seconds. How long will it take the object to reach a height of 16 feet?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The height of an object thrown upward with an initial velocity of 32 feet per second is given by the formula h=-16t^2+32t, where t is the time in seconds. How long will it take the object to reach a height of 16 feet?
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h=-16t^2+32t
Solve for t then h = 16
h=-16t^2+32t = 16
t^2 - 2t + 1 = 0
t = 1 second.
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