SOLUTION: A plane left an airport and flew with the wind for 4 hours, covering 2000 miles. It then returned over the same route to the airport against the same wind in 5 hours. Find the rate

Question 553311: A plane left an airport and flew with the wind for 4 hours, covering 2000 miles. It then returned over the same route to the airport against the same wind in 5 hours. Find the rate of the plane in still air and the speed of the wind.
Answer by prateekagrawal(56) (Show Source): You can put this solution on YOUR website!
in both the cases distance is same.
for case 1 speed is 2000/4 = 500mph
and for case 2 speed is 2000/5 = 400mph.
.
average of sum of these will provide speed of plane.
so, speed of plane =
.
and speed of wind= 500 - 450 = 50mph.
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