SOLUTION: at 7:00am, two joggers start from opposite end of an 8 mile course. one jogger is running at a rate of 4mph, and the other is running at a rate og 6mph. at what time will the jogge

Question 552481: at 7:00am, two joggers start from opposite end of an 8 mile course. one jogger is running at a rate of 4mph, and the other is running at a rate og 6mph. at what time will the joggers meet?
Found 2 solutions by mananth, josmiceli:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
distance = 8 miles
the runners are in opposite directions
so add up speeds
6+4 = 10 mph
t=d/r
8/10 = 4/5 of an hour
4/5 *60 = 48 minutes
They will meet at 7:48 AM
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = time in hrs it takes to meet
Let = distance faster runner goes in hrs
given:
Faster runner:

Slower runner:

-----------
By substitution:

hrs

hrs = 7:48 AM
-------------
check answer:

mi
and

mi
OK
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