SOLUTION: Train A has a speed 5 miles per hour greater than that of train B. Train A travels 195 miles in the same time train B travels 180 miles.
Form the equation that describes the probl
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Question 545806: Train A has a speed 5 miles per hour greater than that of train B. Train A travels 195 miles in the same time train B travels 180 miles.
Form the equation that describes the problem.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
180/x = 195/(x+5)
180(x+5)=195x
180x+900=195x
15x=900
x=60
Train B speed = 60 mph
Train A speed = 65 mph
CHECK
180/60 = 195/65
3=3
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