SOLUTION: please help i'm stuck thank you guys.!! H(T)=-16T(square)+256 they want me to find the Max Hight. Please show me how to find the answer, thank you.

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Question 54179This question is from textbook college algebra
: please help i'm stuck thank you guys.!!

H(T)=-16T(square)+256
they want me to find the Max Hight. Please show me how to find the answer, thank you. This question is from textbook college algebra

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
h%28t%29=-16t%5E2%2B256
t%5E2 tells you that this is a parabola.
The - infront of 16, tells you that this parabola is upside down, so it's vertex would be the highest point of the graph.
To find the x value of the vertex of a quadratic equation that is in standard form highlight%28ax%5E2%2Bbx%2Bc%29, we use the formula:
highlight%28x=-b%2F2a%29
In your case there is no bx, so b=0.
x=-0%2F2%28-16%29
x=0
Substitute that value x=0 into your equation to find y (or h(t)).
h%280%29=-16%280%29%5E2%2B256
h%280%29=0%2B256
h%280%29=256
The highest point is at (0,256).
graph%28300%2C200%2C-20%2C20%2C100%2C270%2C-16x%5E2%2B256%29
Happy Calculating!!!