SOLUTION: A motorboatleaves a harbor and travels at an average speed of 9mph toward a small island. Two hours later, a cabin cruiser leaves the same harbor and travels at an average speed of
Algebra.Com
Question 536996: A motorboatleaves a harbor and travels at an average speed of 9mph toward a small island. Two hours later, a cabin cruiser leaves the same harbor and travels at an average speed of 18mph toward the same island. In how many hours after the cabin cruiser leaves will the cabin cruiser be alongside with the motorboat.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Motorboat speed 9 mph
cabin cruiser 18 mph
Difference in time=> 2 hours
Motorboat will have covered miles before cabin cruiser starts
catch up distance= 18 miles
catch up speed = 18 -9 mph
catch up speed = 9 mph
Catchup time = catchup distance/catch up speed
catch up time= 18 / 9
catch up time= 2 hours
m.ananth@hotmail.ca
RELATED QUESTIONS
A motorboat leaves a harbor at an average speed of 9mph toward a small island. Two hours... (answered by vleith)
A motorboat leaves a harbor and travels at an average speed of 9 mph toward a small... (answered by nerdybill)
a motorboat leaves the harbour and travels at an average speed of 9mph toward a small... (answered by ptaylor)
Hi I am stuck and need some help. Could someone please help me with setting this problem... (answered by checkley75)
A cabin cruiser leaves a harbor and travels to a small island at an average speed of... (answered by richwmiller)
A cabin cruiser leaves a harbor and travels to a small island at an average speed of 24... (answered by stanbon)
A motorboat leaves the harbor at 7 am at the rate of 9 mph towards a small island. Two... (answered by josmiceli)
A cabin cruiser left the harbor and traveled to a small island at 24 mph. On the return... (answered by josmiceli)
Michael Chan leaves a dock in his motorboat and travels at an average speed of 9 mph... (answered by josmiceli)