SOLUTION: PLEASE HELP SOLVE. MULDER LEAVES WASHINGTON AT 8:30AM AND AVERAGES 65MPH. HIS PARTNER, SCULLY, LEAVES AT 9:00AM FOLLOWING THE SAME PATH AND AVERAGING 68MPH. AT WHAT TIME WILL SC

Question 53662: PLEASE HELP SOLVE.
MULDER LEAVES WASHINGTON AT 8:30AM AND AVERAGES 65MPH. HIS PARTNER, SCULLY, LEAVES AT 9:00AM FOLLOWING THE SAME PATH AND AVERAGING 68MPH. AT WHAT TIME WILL SCULLY CATCH UP WITH MULDER.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
MULDER LEAVES WASHINGTON AT 8:30AM AND AVERAGES 65MPH. HIS PARTNER, SCULLY, LEAVES AT 9:00AM FOLLOWING THE SAME PATH AND AVERAGING 68MPH. AT WHAT TIME WILL SCULLY CATCH UP WITH MULDER.
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Mulder DATA:
rate=65 mph ; time= x hrs. ; distance= rt=65x miles
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Scully DATA:
rate=68 mph ; time= x-(1/2)=(2x-1)/2 hrs ;
distance= rt= 68(2x-1)/2= 34(2x-1)=68x-34 miles
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EQUATION:
distance = distance
65x=68x-34
3x=34
x=11 1/4 hrs or 11hr 15 min
The time will be 8:30AM + 11hr 15 min
I'll let you figure that out.
Cheers,
Stan H.

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